Calculate the concentration of the chromic ion in the cell which has an electrode potential of 0.688 at 298.15 K for the given reaction:

Cr2O7 2 – (aq) + 14 H+ (aq) + 6 I – 1 (aq) → 2 Cr 3+(aq) + 3I2(s) + 7 H2O(l)

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