A 458 mL of water at 21.5 â°C is in a calorimeter. If a 758.7 g gold at 99.7 â°C is put into the calorimeter, the temperature becomes 25.3 â°C. Sp. Heat of Gold = 0.129 J/g-K
If the calorimeterâs heat capacity is 1.53 J/K, what will the final temperature be if the same gold with the same initial temperature is added?