A 458 mL of water at 21.5 ⁰C is in a calorimeter. If a 758.7 g gold at 99.7 ⁰C is put into the calorimeter, the temperature becomes 25.3 ⁰C. Sp. Heat of Gold = 0.129 J/g-K

If the calorimeter’s heat capacity is 1.53 J/K, what will the final temperature be if the same gold with the same initial temperature is added?

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